1.

a ball moving with momentum of 5kgm /sec strikes against a wall at an angle of 45 degree and is reflected at the same angle. Calculate the change in momentum​

Answer»

Given :-

<P>
  • P = 5kgm/s
  • Θ = 45°

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From the figure given above, there is no change in perpendicular component and cancel each other.

The initial momentum along the x - axis,

\bf\green{P = P \cos \: Θ }

The final momentum along the x-axis,

\bf\green{P{f}= - P \cosΘ}

So, change in momentum

\bf\green{∆ \: P = Pf - Pi } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \bf\green{∆ \: P = - 2P \cosΘ} \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \bf\green{∆ \: P = - 2 \times 5 \times \cos45°} \\ \bf\green{∆ \: P = - 7.071kgm/s} \: \: \: \:

Change in momentum is -7.071 kgm/s


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