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A ball of mass 0.2 kg is thrown against the wall . the ball strikes the wall normally with velocity of 30m/sand rebounds with velocity of 20m/s. calculate the impulse of the force exerted by the ball on the wall |
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Answer» m = 0.2 kg u = 30 m/s v = 20 m/s impulse = change in the MOMENTUM final momentum - initial momentum mv - mu m ( v - u ) => 0.2 * (-20 -30 ) = -10 Ns |
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