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A ball of mass `1kg` hangs in equilibrium from two strings as shown in If `g = 10m//s^(2)` what are the valuse of tension in strings `OA` and `OB` . |
Answer» Correct Answer - `5 N ; 5sqrt3N` . As shown in the three force `T_(1), T_(2)` and mg acting at`O` are in equilibrium Applying Lami s theorem we get `(T_(1))/(sin 150^(@)) =(T_(2))/(sin 120^(@)) = (mg)/(sin90^@)` `T_(1) = (mg)/(sin 90^(@)) xxsin 150^(@) = (10 sin 30^(@))/(1) = 5 N` `T_(2) = (mg)/(sin90^(@)) xxsin120^(@) = (10sqrt3//2)/(1) = 5 sqrt3N` . |
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