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a ball of mass 200 g falls from a height of 2.0 m . what is the kinetic energy of the ball when it reaches the ground ? take g = 9.8 m/s^2 |
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Answer» m = 200 G = 200/1000 kg = 200 * 10^-3 H = 2 m g = 9.8 m/s to calculate k.e. of the ball reaches the ground = ? P.E. at the top = P.E. at the ground = MGH = ( 200 * 10^-3 )9.8 * 2 = 3.92 joules therefore , K.E. of the ball when it reaches the ground is same as P.E. at the top => 3.92 J |
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