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A ball of mass `m_(1)` and another ball of mass `m_(2)` are dropped from equal height. If the time taken by the balls are `t_(1)` and `t_(2)`, respectively, thenA. `t_(1)=t_(2)`B. `t_(1)=2t_(2)`C. `t_(1)/t_(2)=m_(1)/m_(2)`D. `t_(1)/t_(2)=m_(2)/m_(1)` |
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Answer» Correct Answer - A Time is independent of mass. `h=1/2g t_(1)^(2)=1/2g t_(2)^(2)impliest_(1)=t_(2)` |
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