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A ball of mass 'm' is thrown at an angle of ' θ ' with the horizontal with an initial velocity 'u'. The change in its momentum during its flight in a time interval of’t’ is1) mgt 2) mgt cosθ 3) mgtsinθ 4) 1/2 mgt |
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Answer»
4-1/2mgt
We KNOW that, v−u=−gt⟹u−v=gt→(1) MULTIPLY with m. mu−mv=mgt Change in its momentum=mgt Where=U=usinθ |
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