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A ball rolling on ice with a velocity of `4 .9 m//s` stops after travelling 4 m . If `g = 9.8 m//s^(2)` what is the coefficient of friction ? |
Answer» Here , ` u = 4.9 m//s , upsilon = 0 , s = 4 m ` ` g = 9.8 m//s^(2) , mu = ` ? ` upsilon^(2) - u^(2) = 2 as = 2 (-mu g ) s ` ` mu= (upsilon^(2) - u^(2))/(-2gs) = (0-(4.9)^(2))/(-2 xx 9.8 xx 4 )= 0.31 ` . |
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