A ball thrown vertically upwards after reaching maximum height h retur

1.	A ball thrown vertically upwards after reaching maximum height h returns to the starting point after a time of 10 s. Its displacement after 5 s is (d) 20 h (c) 10h (b) 2h (a) h
Answer» Answer: EXPLANATION: DISTANCE after time 10 second S=ut +1/2at^2 h=0t+1/210*10^2 h=0+500 h=500m Now at 5s It is at 125 m Displacement = 375 m

A ball thrown vertically upwards after reaching maximum height h returns to the starting point after a time of 10 s. Its displacement after 5 s is (d) 20 h (c) 10h (b) 2h (a) h

Answer»

Answer:

EXPLANATION:

DISTANCE after time 10 second

S=ut +1/2at^2

h=0*t+1/2*10*10^2

h=0+500

h=500m

Now at 5s

It is at 125 m

Displacement = 375 m

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A ball thrown vertically upwards after reaching maximum height h returns to the starting point after a time of 10 s. Its displacement after 5 s is (d) 20 h (c) 10h (b) 2h (a) h

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