A ballon is ascending at the rate `v = 12 km//h` and is being carried horizontally by the wind at `v_(w) = 20 km//h`. If a ballast bag is dropped from the balloon at the instant h = 50 m, determine the time needed for it to strike the ground. Assume that the bag was released from the ballon with the same velocity as the balloon. Also, find the speed with which the bag strikes the ground?

A ballon is ascending at the rate `v = 12 km//h` and is being carried

1.	A ballon is ascending at the rate `v = 12 km//h` and is being carried horizontally by the wind at `v_(w) = 20 km//h`. If a ballast bag is dropped from the balloon at the instant h = 50 m, determine the time needed for it to strike the ground. Assume that the bag was released from the ballon with the same velocity as the balloon. Also, find the speed with which the bag strikes the ground?
Answer» Correct Answer - B::C `u_x = 20 km//h = 20 xx 5/18 = 5.6 m//s` `u_y = 12 km//h` `= 12 xx 5/18 = 3.3 m//s` Using `S = ut + 1/2 at^2` in vertical direction, we have `-50 = (3.3) t + 1/2 (-10) t^2` Solving this equaiton we get, `t = 3.55 s` At the time of striking with ground, `v_x = u_x = 5.6 m//s` `v_y = u_y + a_yt` `= (3.3) + (-10) (3.55)` `=32.2 m//s` `:. Speed = (sqrt(32.2)^2 + (5.6)^2)` ` ~~ 32.7 m//s`.

Discussion

No Comment Found

Related InterviewSolutions

A threaded rod with `12 turns//cm` and diameter `1.18 cm` is mounted horizontally. A bar with a threaded hole to match the rod is screwed onto the rod. The bar spins at `216 rev//min`. How long will it take for the bar to move `1.50 cm` along the rod ?
A ballon is ascending at the rate `v = 12 km//h` and is being carried horizontally by the wind at `v_(w) = 20 km//h`. If a ballast bag is dropped from the balloon at the instant h = 50 m, determine the time needed for it to strike the ground. Assume that the bag was released from the ballon with the same velocity as the balloon. Also, find the speed with which the bag strikes the ground?
A particle is dropped from point P at time t = 0. At the same time another particle is thrown from point O as shown in the figure and it collides with the particle P. Acceleration due to gravity is along the negative y-axis. If the two particles collide 2 s after they start, find the initial velocity `v_0` of the particle which was projected from O. Point O is not necessarily on ground.
Two bodies are thrown with the same intial velocity at angles ` theta ` and `(90^@ - theta)` respectively with the horizontal, then their maximum height are in the ratioA. 1 : 1B. ` sintheta : costheta`C. `sin^2theta:cos^2theta`D. `costheta:sintheta`
Identify the correct statement related to the projectile motion.A. It is uniformly accelerated everywhereB. It is uniformly accelerated everywhere except at the highest position where it is moving with constant velocityC. Acceleration is never perpendicular to velocityD. None of the above
A particle is projected with velocity u at angle `theta` with horizontal. Find the time when velocity vector is perpendicular to initial velocity vector.
A grass hopper can jump maximum distance `1.6m.` It spends negligible time on ground. How far can it go in `10(sqrt2)`s?A. 45 mB. 30 mC. 20 mD. 40 m
Two stones are projected with the same speed but making different angles with the horizontal. Their horizontal ranges are equal. The angle of projection of one is `pi/3` and the maximum height reached by it is 102 m. Then the maximum height reached by the other in metres isA. 76B. 84C. 56D. 34
The maximum vertical height of a projectile is 10 m. If the magnitude of the initial velocity is `28 ms^(-1)`, what is the direction of the initial velocity. ? Take `g = 9.8 ms^(-2)`.
Show that there are two values of time for which a projectile is at the same height. Also show mathematically that the sum of these two times is equal to the time of flight.

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment