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    				| 1. | Two stones are projected with the same speed but making different angles with the horizontal. Their horizontal ranges are equal. The angle of projection of one is `pi/3` and the maximum height reached by it is 102 m. Then the maximum height reached by the other in metres isA. 76B. 84C. 56D. 34 | 
| Answer» Correct Answer - D `H_1 = (u^2sin^2theta)/(2g)` `:. 102 = ((u)^2sin^(2)60^@)/20` `:. u = 52.2 m//s` Other stone should be projected at `90^@-theta` or `30^@` form horizontal. `:. H_2 = (u^2 sin^2 30^@)/(2g)` `=((52.2)^2(1//4))/20` =34m. | |