1.

Two stones are projected with the same speed but making different angles with the horizontal. Their horizontal ranges are equal. The angle of projection of one is `pi/3` and the maximum height reached by it is 102 m. Then the maximum height reached by the other in metres isA. 76B. 84C. 56D. 34

Answer» Correct Answer - D
`H_1 = (u^2sin^2theta)/(2g)`
`:. 102 = ((u)^2sin^(2)60^@)/20`
`:. u = 52.2 m//s`
Other stone should be projected at `90^@-theta` or `30^@` form horizontal.
`:. H_2 = (u^2 sin^2 30^@)/(2g)`
`=((52.2)^2(1//4))/20`
=34m.


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