1.

A balloon of mass M is descending at a constantacceleration α. When a mass m is released from theballoon it start rising with the same acceleration c..Assuming that its volume does not change, what 1sthe value of m?2αα+g2αα+g

Answer»

Let the force due to buoyancy be B.

In the first case the equation will be

Mg - B = Ma

In the second case the equation will be

B - (M-m)g = (M-m)a

Since the volume is unchanged, the force of Buoyancy remains unchanged as same amount of air is displaced even now and the new mass is (M-m)

Adding the two equations we get,

mg = (2M-m)a

or m(g+s)=2Ms

or m=2Ma/(g+a)

Let the force due to buoyancy be B.

In the first case the equation will be

Mg - B = Ma

In the second case the equation will be

B - (M-m)g = (M-m)a

Since the volume is unchanged, the force of Buoyancy remains unchanged as same amount of air is displaced even now and the new mass is (M-m)

Adding the two equations we get,

mg = (2M-m)a

or m(g+a)=2Ma

or m=2Ma/(g+a)


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