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A balloon starting from rest ascends vertically with uniform acceleration to a height of 100m is 10s. The force on the bottom of the balloon by a mass of 50 kg us (`g=ms^(-2)`)A. 100 NB. 300 NC. 600 ND. 400 N |
Answer» Correct Answer - C ( c) Given that, h=100m and t=10s From equation of motion, `h=(1)/(2) at^(2)` `a=(2h)/(t^(2))=(2xx100)/((10)^(2))=2 ms^(-2)` Now, `F=50(10+2) implies F=600 N` |
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