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A bar measured with a vernier caliper is found to be 180 mm long. The temperature during the measurement is `10^@C`. The measurement error will be if the scale of the vernier caliper has been graduated at a temeprature of `20^@C`. (`alpha=1.1xx10^(-5).^(@)C^(-1)`. Assume that the length of the bar does not change.)A. `1.98 xx 10^(-1) mm`B. `1.98 xx 10^(-2)mm`C. `1.98 xx 10^(-3)mm`D. `1.98 xx 10^(-4)mm` |
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Answer» True measurement =scale reading `[1 + alpha (theta - theta_(0))]` `= 180 [1- 10 xx 1.1 xx 10^(-5)]` error `= 180 - 180 [1-1.1 xx 10^(-4)] = 1.98 xx 10^(-2) mm` |
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