A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω , 0.5 Ω and 12 Ω, respectively. How much current would flow through the 12 Ω resistor

A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3

1.	A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω , 0.5 Ω and 12 Ω, respectively. How much current would flow through the 12 Ω resistor
Answer» Explanation:According to Ohm’s lawV= IRTherefore, I= V/RWhere,R is the EQUIVALENT resistance of resistances 0.2 Ohm, 0.3 Ohm, 0.4Ohm, 0.5 Ohm and 12 Ohm.These are connected in series.Hence, the sum of the resistances will give the value of R.R= R1 + R2 + R3 + R4 + R5= 0.2 + 0.3 + 0.4 + 0.5 + 12 = 13.4 OhmThe potential difference, V= 9 VI = 9/13.4 = 0.671 AWHEN resistors are connected in series, the current is the same in all the resistors. Hence, current in 12 Ω resistor = 0.67 A.

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A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω , 0.5 Ω and 12 Ω, respectively. How much current would flow through the 12 Ω resistor​

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A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω , 0.5 Ω and 12 Ω, respectively. How much current would flow through the 12 Ω resistor