1.

A battery of e.m.f 3.0 V supplies current through a circuit in which the resistance can be changed. A high resistance voltmeter is connected across the battery. When the current is 1.5 A, the voltmeter reads 2.7 V. Find the internal resistance of the battery.

Answer»

ε = 3 volt

I = 1.5 A

V = 2.7 V

V = ε − Ir

r = (e-V) / I

= (3 – 2.7) / 1.5 = 0.2 ohm



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