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) A battery of emf 6 V and internal resistance 2 Ω is connected in parallel with another battery of emf 5 V and internal resistance 2 Ω . The combination is used to send a current through an external resistance of 8 Ω . Calculate the current through the external resistance |
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Answer» mark me Brainliest Explanation: A BATTERY of emf 4 volts and internal resistance 1Ω is connected in parallel with another battery of emf 1 volt Combination is used to send current through an external resistance 2Ω. Calculate current through external resistance and potential difference across external resistance. equation: V 1 =4v R 1 =1Ω V 2 =1v R 2 =0Ω 'Total current from the combination=current FLOWING 2Ω=I ∴I= R 1 −R 2
v 1 −v 2
= 1+0 4−1 A =3A Potential difference across 2Ω=(3×2)v =6v i HOPE this works |
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