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A beam of natural light falls on a system of 6 polaroids, which are arranged in succession such that each polaroid is turned through `30^@` with respect to the preceding one. The percentage of incident intensity that passes through the system will beA. 1B. 0.5C. 0.3D. 0.12 |
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Answer» Correct Answer - D If n polaroids are arranged in succession such that each is turned through `theta` with respect to preceding then the intensity of `n^(th)` polaroid is `I_(n) = (I_(0))/(2) (cos^(2) theta)^(n-1)` `I_(6) = (I_(0))/(2) (cos^(2) 30)^(5) = (I_(0))/(2) xx (3)/(4)xx (3)/(4)xx (3)/(4)xx (3)/(4)xx (3)/(4)` `(I_(6))/(I_(0)) = (243)/(2048) = 0.1186 ~~ 12%` |
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