InterviewSolution
Saved Bookmarks
| 1. |
The change in wavelenght of light of frequency `4 xx 10 ^(14)`Hz. When it pass from air to glass, is `( mu_("glass") = 1.5)`A. 2500 ÅB. 3500 ÅC. 3000 ÅD. 2000 Å |
|
Answer» Correct Answer - A `lambda_(a) = (v_(a))/(n) = (3 xx 10^(8))/(4 xx 10^(14)) = 0.75 xx 10^(-6) = 7500 Å` `lambda_(g) = (lambda_(g))/(mu_(g)) = (7500)/(1.5) = 5000 Å` `lambda_(a) - lambda_(g) = 7500 - 5000 = 2500 Å` |
|