1.

A wave of light having frequency `4 xx 10^(14)`Hz. And speed of light `3 xx 10^8` m/s enters glass of R.I. 1.5. Change in wavelength isA. `2.5 xx 10^(-7) m`B. `2.5 xx 10^(-6) m`C. `2.5 xx 10^(-8)m`D. `2.5 xx 10^(-9)m`

Answer» Correct Answer - A
`lambda_(a) = (v_(a))/(n) = (3 xx 10^(8))/(4 xx 10^(14)) = 0.75 xx 10^(-6)`
`= 7500 Å`
`lambda_(g) = (lambda_(a))/(mu_(g)) = (7500)/(1.5) = 5000Å`
`lambda_(a) - lambda_(g) = 7500 - 5000 = 2500 Å`


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