A block `A`is just placed inside a smooth box `B` as shown in figure. Now the box is given an acceleration `a = (2 hat(i) - 2 hat(j)) m//s ^(-2)`. Under the acceleration block `A` cannot remain in the position shown. Block will require `ma` force for moving with acceleration `a`.A. If both Accertion and Reason are true and the reason is correct explanation of the Assertion.B. If both Assertion and Reason are true but reason is not the correct explanation of Assertion.C. If Assertion is true, but the Reason is false.D. If Assertion is false but the Reason is true.

A block `A`is just placed inside a smooth box `B` as shown in figure.

1.	A block `A`is just placed inside a smooth box `B` as shown in figure. Now the box is given an acceleration `a = (2 hat(i) - 2 hat(j)) m//s ^(-2)`. Under the acceleration block `A` cannot remain in the position shown. Block will require `ma` force for moving with acceleration `a`.A. If both Accertion and Reason are true and the reason is correct explanation of the Assertion.B. If both Assertion and Reason are true but reason is not the correct explanation of Assertion.C. If Assertion is true, but the Reason is false.D. If Assertion is false but the Reason is true.
Answer» Correct Answer - B For `(-2hat(i))m//s^(2)` component of acceleration , a horizontal force in `- ve x -` direction is required which can be provided only by the right vertical wall of the box.

Discussion

No Comment Found

Related InterviewSolutions

A horizontal force of `1.2kg` is applied on a `1.5kg` block, which rests on a horizontal surface If the coefficient of friction is `0.3` find the acceleration produced in the block.
A block of mass m slides down on a wedge of mass M as shown in figure .Let `a_(1)` be the asseleration of the acceleration of and `a_(2)` the the acceleration od block 1`N_(1)` is the normal reaction between block and wedge and `N_(2)` the normal reaction between wedge and gound .frication is absent everwhere .Select the correct alternative(s) A. `N_(2)lt(M+m)g`B. `N_(2)ltM(g cos theta-|a_(1)|sintheta)`C. `N_(1)sin theta=M|a_(1)|`D. `ma_(2)=-Ma_(1)`
A hammer weighing 3 kg moving with a velocity of `10ms^(-1)` strikes against the head fo a spike and drives it into a block of wood. If the hammer comes to rest in `0.025` s, find (i) the impulse and (ii) the average force on the head of the spike.
A man of mass 70 kg stands on a weighing machine in a lift, which is moving (a) upwards with a uniform speed of `10ms^(-1)` (b) downwards with a uniform acceleration of `5 ms^(-2)` (c) upwards with a uniform acceleration of `5 ms^(-2)` What would be the readings on the scale in each case ? (d) What would be the reading if the lift mechanism failed and it hurtled down freely under gravity ?
A body wights 8 g when placed on one pan and 18 g when placed on the other pan of a false balance .If the beam is horizontal when both the pans are empty the weght of the body is 4 xg Find value of x.
A racing car travels on a track (without banking) ABCDEFA ABC is a circular are of radius ` 2 R.CD` and `FA` are strainght paths of length `R` and `DEF` is a circular are of radius `R=100m` The co- efficient of friction on the road is `mu = 0.1` The maximum speed of ther car is `50ms^(-1)` Find the minimum time for completing one round .
A constant force acting on a body of mass of 5 kg change its speed from `5ms^(-1) "to" 10ms^(-1)` in 10 s without changing the direction of motion. The force acting on the body isA. 1.5NB. 2NC. 2.5ND. 5N
Given the magnitude and direction of the force acting on a stone of mass 0.1 kg (a) just after it is dropped from the window of a stationary train (b) just after it is dropped from the window of a train running at a constant velocity of `36 km//hr` (c) just after it is droped from the window of a train accelerating with `1 ms^(-2)` (d) lying on the floor of a trin which is accelerating with `1 ms^(-2)` the stone being at rest relative to the train . Neglect the resistance of air throuhout .
When forces `F_1`, `F_2`, `F_3`, are acting on a particle of mass m such that `F_2` and `F_3` are mutually perpendicular, then the particle remains stationary. If the force `F_1` is now removed then the acceleration of the particle isA. (a) `F//m`B. (b) `F_2F_3//mF_1`C. (c) `(F_2-F_3)//m`D. (d) `F_2//m`
If a body looses half of its velocity on penetrating 3 cm in a wooden block, then how much will it penetrate more before coming to rest?A. (a) 1 cmB. (b) 2 cmC. (c) 3 cmD. (d) 4 cm

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment