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A block `B` is pushed momentarily along a horizontal surface with an initial velocity `v` . If mu is the coefficient of sliding friction between `B` and the surface, block `B` will come to rest after a time: A. `(v)/(mug)`B. `(vg)/(g)`C. `(v mu)/(g)`D. `(mu g)/(v)` |
Answer» Correct Answer - A (a) Given, initial velocity =v Final velocity =0 coefficient of friction =`mu` For a straight line motion , v-u=at Here, `0-v=-(mu g)t" "(as,a=(mu mg)/(m))` Negative sign indicates retardation. `therefore" " t=(v)/(mu g)` |
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