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A block is gently placed on a conveyor belt moving horizontal with constant speed After `t = 4s` the velocity of the block becomes equal to velocity of the belt If the coefficient of friction between the block and the belt is `mu = 0.2`, then the velocity of the conveyor belt is .A. `8//s`B. `6m//s`C. `4m//s`D. `2m//s` |
Answer» Correct Answer - a On account of friction `(a =mu g)` velocity of block will become equal to velocity of block will become equal to velocity of conveyor belt and the relative motion between the two will stop `upsilon = at = mu g t =0.2 xx 10 xx 4 = 8m//s` . |
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