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A block is gently placed on a conveyor belt moving horizontal with constant speed After `t = 4s` the velocity of the block becomes equal to velocity of the belt If the coefficient of friction between the block and the belt is `mu = 0.2`, then the velocity of the conveyor belt is .A. `8 ms^(-1)`B. `4 ms^(-1)`C. `6 ms^(-1)`D. `18 ms^(-1)` |
Answer» Correct Answer - A (a) Due to friction (`a=mug)`, velocity of block will become equal to velocity of belt. Relative motion between two will stop. `therefore" "v=at=mug=0.2xx10xx4=8 ms^(-1)` |
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