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A block of base `10cmxx10cm` and height 15cm is kept on an inclined plane. The coefficient of friction between them is `sqrt3`. The inclination `theta` of this inclined plane from the horizontal plane is gradually increased from `0^@` ThenA. at `theta=30^@` the block will start sliding down the planeB. the block will remain at rest on the plane up to certain `theta` and ten it will toppleC. at `theta=60^@` the block will start slidng down the plane and continue to do so at higher anglesD. at `theta=60^@` the block will start sliding down the plane and on further increasing `theta`, it will topple at certain `theta` |
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Answer» Correct Answer - B For sliding `tanthetagesqrt(3)(=1.732)` For toppling `tanthetage2/3(=0.67)` |
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