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A block of mass 10 kg is sliding on a surface inclined at `30^(@)` with horizontal . If coefficient of friction between the block and the surface is 0.5 , find acceleration produced in the block . Take ` g = 9.8 m //^(2)` . |
Answer» Here , ` 10 kg , theta = 30^(@) , mu = 0.5 , ` ` a = ? ` ` a = g ( sin theta - mu cos theta) ` ` = 9.8 (sin 30^(@)) = 0.657 m // s^( 2 ) ` . |
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