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A block of mass 1kg sliding on a smooth horizontal surface with a speed of 2ms^-1meet the free end of a long horizontal spring fixed at the other end having a spring constant 0.25Nm^-1. Find the meximum compression of the spring to bring the block of mass momentarily at rest. |
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Answer» Answer: Here we can use conservation of energy since no external agencies are acting. K.E = Elastic potential energy 1/2mv^2 = 1/2kx^2 1kg × 4 = 0.25 × X^2 16 = x^2 Thus x = 4m compression Mark as BRAINLIEST PLEASE |
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