1.

A block of mass 2 kg is lying on a floor. The coefficient of kinetic friction is 0.4 If a force of 2 5 N is applied onthe block as shown in the figure, then the magnitude of frictional force will be(a) 7.5 N(c) 2.5 N(UPSEAT 2002(b) 10 N(d) 5 N

Answer»

given that ,

》mass of block = 2kg

》force applied = 2.5

》coefficient of static friction, µs= 0.4

☆Maximum static frictional force,

fmax = µs× m × g = 0.4 × 2 × 9.8

=> fmax= 7.84 N

Since,

the applied force is less than the maximum static frictional force,

the frictional force on the block is equal to the applied force = 2.5 N.

☆it is due to the fact that static friction is a self adjusting force.



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