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A block of mass 2kg rests on a rough inclined plane making an angle of `30^@` with the horizontal. The coefficient of static friction between the block and the plane is 0.7. The frictional force on the block isA. 9.8 NB. `0.7xx9.8xxsqrt(3) N`C. `9.8xxsqrt(3) N`D. `0.7xx9.8 N` |
Answer» Correct Answer - A (a) Angle of respose `theta_(r)=tan ^(-1)(mu_(s))=tan^(-1)(0.7)` or `tan theta_(r)=0.7` Angle of plane is `theta=30^(@), tan theta= tan 30^(@)=0.577` Since`" " tan theta lt tan theta_(r), theta lt theta_(r)` Block will not slide or `f= mg sin theta ne mu mg cos theta` or `" " f=(2)(9.8) sin 30^(@)=9.8 N` |
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