A block of mass 5 kg is placed on a rough table. the coefficient of static and kinetic friction between surfaces of block and table be 0.4 and 0.3 respectively. if the force F exerted on the block is 10N (g=10m/s^2) the force of friction between the block and the table is ------------------.explain briefly.

A block of mass 5 kg is placed on a rough table. the coefficient of st

1.	A block of mass 5 kg is placed on a rough table. the coefficient of static and kinetic friction between surfaces of block and table be 0.4 and 0.3 respectively. if the force F exerted on the block is 10N (g=10m/s^2) the force of friction between the block and the table is ------------------.explain briefly.
Answer» Mass of BLOCK = 5 kg coefficient of static friction, $\mu_s$ = 0.4 coefficient of kinetic friction $\mu_k$ = 0.3 limiting friction = $\mu_s$ ×m×g=0.4×5×10 = 20N Until a force greater than 20N is applied, the block won't MOVE. For any force F ≤ limiting friction, the value of friction will be F since friction is a self-adjusting force. So when a force 10N is applied, the friction between block and table is 10N.

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