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. A block of unknown mass is at rest on a rough, horizontal surface (unmal force can be vary from 30s to 90°A horizontal force F is appliedto the block. The graph in the figure shows the acceleration of the block with respect to the applied force.The mass of the block isμ4-ト-+-+-+-+- r:0:哎--|ーマ6810-12-14ーApplied force FIN)(D) 0.2 kg山一(A) 1.0 kg(B) 0.1 kg(C) 2.0 kg |
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Answer» from the figure.. the Frictional force is = 4N after which the block starts to accelerates so, now at final force = 14N and a = 5 => F-f = m*a => 14-4 = m*5=> 10 = 5m=> m = 10/5 = 2kg |
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