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A block of wood, specific gravity 0.6 and mass 90.0 g is floting in water. A hole is drilled in it removing 8.0 g of wood. The hole is filled with lead of density `11.43 g//cm^(3)`. What will be the effect on the block? |
Answer» The block will sink. The same is explained below. Volume of the block, `V =(mass)/(density) = (90.0)/(0.6) = 150 cm^(3)` Mass of the wood removed` = 8.0 g`, volume of the hole from which the wood is removed = ` (8.0)/(0.6) = 40/3 cm^(3)` Volume of lead inserted in block `= 40/3 cm^(3)` Mass of lead in block = `40/3 xx 11.34 = 151.2 g` Total mass of block with lead `=(90-8)+151.2 = 233.2g` when the whole block is in water, volume of the water displaced = `150 cm^(3)` Weight of water displaced =` 150 xx 1 = 150 gf`, Which is less than the weight of the block. so the block will sink. |
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