❄️ A block whose nass is 2 kg is fastened to a spring. The spring

1.	❄️ A block whose nass is 2 kg is fastened to a spring. The spring has a constant of 50 N/m. The block is pulled to a distance x= 10 cm from its equilibrium postion at x=0 on a frictionless surface from rest rest at t= 0. Calculate the. kinetic, potential and total energies of the block when it is 5 cm away from the mean postion.# don't spam :P
Answer» $\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$ MASS= 2kg Spring constant = 50N/m Distance x=10cm X=0 t=0 Kinetic and POTENTIAL energy of the block = 5 CM AWAY from the MEAN position $angular \: frequency \: (w) = \sqrt{k \div m} \\ w = \sqrt{100 \div 2} \\ w = \sqrt{50} \\ w = 7.071rads {}^{-} \\$ $Its \: displacement \: at \: any \: time(t) \: is \: given \: by \: x(t) = (0.1)cos(7.07t) \\ pe = 1 \div 2kx {}^{2} \\ = 1 \div 2(50)(0.1) {}^{2} \\ = 25 \times 0.01 \\ = 0.25j$

❄️ A block whose nass is 2 kg is fastened to a spring. The spring has a constant of 50 N/m. The block is pulled to a distance x= 10 cm from its equilibrium postion at x=0 on a frictionless surface from rest rest at t= 0. Calculate the. kinetic, potential and total energies of the block when it is 5 cm away from the mean postion.# don't spam :P

Answer»

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$

MASS= 2kg

Spring constant = 50N/m

Distance x=10cm

X=0

t=0

Kinetic and POTENTIAL energy of the block = 5 CM AWAY from the MEAN position

$angular \: frequency \: (w) = \sqrt{k \div m} \\ w = \sqrt{100 \div 2} \\ w = \sqrt{50} \\ w = 7.071rads {}^{-} \\$

$Its \: displacement \: at \: any \: time(t) \: is \: given \: by \: x(t) = (0.1)cos(7.07t) \\ pe = 1 \div 2kx {}^{2} \\ = 1 \div 2(50)(0.1) {}^{2} \\ = 25 \times 0.01 \\ = 0.25j$

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