A body covered a distance of 5 m along a semicircular path. The ratio of distance to displacement is(A) 11:7(C) 5:12(B) 12:5(D) 7:11

A body covered a distance of 5 m along a semicircular path. The ratio

1.	A body covered a distance of 5 m along a semicircular path. The ratio of distance to displacement is(A) 11:7(C) 5:12(B) 12:5(D) 7:11
Answer» els SEMICIRCULAR pathDistance = πr5 = πrr = 5/πDisplacement = Distance between initial position and final position= 2r= 2 * 5/π= 10/π metresRatio of distance to DISPLACEMENT= 5 / (10 / π)= π/2= 11/7= 11 : 7

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A body covered a distance of 5 m along a semicircular path. The ratio of distance to displacement is(A) 11:7(C) 5:12(B) 12:5(D) 7:11​

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A body covered a distance of 5 m along a semicircular path. The ratio of distance to displacement is(A) 11:7(C) 5:12(B) 12:5(D) 7:11