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A body executes simple harmonic motion according to following equation.X=5.0cos[2πt+π4] m where t=1.5 s, calculate 1 displacement 2 velocity 3 acceleration |
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Answer» Answer: x = -5/√2 m. v = 10π/√2= 22.21 m/s a= 20π^2/√2= 139.58 m/s^2 Explanation: 1. displacement at t=1.5=3/2 is x=5 COS[3π+π/4] = -5/√2m. 2. VELOCITY (v) = dx/dt= -10π SIN[2πt+π/4] at t=1.5=3/2, v = 10π/√2= 22.21 m/s acceleration (a) = dv/dt = -20π^2 cos[2πt+π/4] at t=1.5=3/2, a= 20π^2/√2= 139.58 m/s^2 |
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