A body falls freely from a height of 125 m `(g=10 m//s^(2))`. After 2 sec gravity ceases to act find time taken by it to reach the ground?

A body falls freely from a height of 125 m `(g=10 m//s^(2))`. After 2

1.	A body falls freely from a height of 125 m `(g=10 m//s^(2))`. After 2 sec gravity ceases to act find time taken by it to reach the ground?
Answer» Distance covered in 2s under gravity `S_(1)=(1)/(2)g t^(2)=(1)/(2)(10)(2)^(2)=20m` Velocity at the end of 2s `V=g t=10 xx2=20 m//s` Now at this instant gravity ceases to act, there after velocity becomes constant. The remaining distance which is `125-20=105m` is covered by body with constant velocity `20 m//s` time taken to cover 105 m with constant velocity is given by `t_(1)=(S)/(V)impliest_(1)=(105)/(20)=5.25s` Total time taken `=2+5.25=7.25s`

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A body falls freely from a height of 125 m `(g=10 m//s^(2))`. After 2 sec gravity ceases to act find time taken by it to reach the ground?

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