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A body falls from rest in the gravitational field of the earth.The distance travelled in the fifth second of its motion is(g-10m/s)(a) 25 m(c) 90 m(b) 45 m(d) 125 m |
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Answer» Hn = (g/2)(2n - 1)H5 = (10/2)(2×5 - 1) = 5 × 9 = 45m s=u+a/2(2n-1) u is 0a is 10n is 5 therefore s will be 45 m |
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