A body is executing simple harmonic motion with an angular frequency o

1.	A body is executing simple harmonic motion with an angular frequency of 2 Rad/sec. The velocity of the body at 20mm displacement, when the amplitude of the motion is 60 mm is?can u help me with solution?
Answer» The EQUATION of MOTION: $y=A \sin \omega t\\A=60 \times 10^{-3}m\\\omega=2\\\frac{dy}{dt}=v=A\omega \cos \omega t\\v=(6\times 10^{-2}) \times 2 \times \sqrt{2}/3\\v=4\sqrt{2} \times 10^{-2}m/sec$

A body is executing simple harmonic motion with an angular frequency of 2 Rad/sec. The velocity of the body at 20mm displacement, when the amplitude of the motion is 60 mm is?can u help me with solution?

Answer»

$y=A \sin \omega t\\A=60 \times 10^{-3}m\\\omega=2\\\frac{dy}{dt}=v=A\omega \cos \omega t\\v=(6\times 10^{-2}) \times 2 \times \sqrt{2}/3\\v=4\sqrt{2} \times 10^{-2}m/sec$

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A body is executing simple harmonic motion with an angular frequency of 2 Rad/sec. The velocity of the body at 20mm displacement, when the amplitude of the motion is 60 mm is?can u help me with solution?

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