a body is moving along a circular path of diameter 200m it take 40 min

1.	a body is moving along a circular path of diameter 200m it take 40 minutee to complete one round calculate the distance and displacement at the end of 2 minutes 20 seconds
Answer» Answer: 200m Explanation: Diameter of circular track (D) = 200 m Radius of circular track (r) = 200 / 2=100 m Time taken by the ATHLETE for one round (t) = 40 s Distance covered by athlete in one round (s) = 2π r = 2 × ( 22 / 7 ) × 100 Speed of the athlete (v) = Distance / Time = (2 × 2200) / (7 × 40) = 4400 / 7 × 40 Therefore, Distance covered in 140 s = Speed (s) × Time(t) = 4400 / (7 × 40) × (2 × 60 + 20) = 4400 / (7 × 40) × 140 = 4400 × 140 /7 × 40 = 2200 m Number of round in 40 s =1 round Number of round in 140 s =140/40 =3 1/2 Hence, DISPLACEMENT of the athlete with respect to initial POSITION at x= xy = Diameter of circular track = 200 m

a body is moving along a circular path of diameter 200m it take 40 minutee to complete one round calculate the distance and displacement at the end of 2 minutes 20 seconds

Answer»

Answer:

200m

Explanation:

Diameter of circular track (D) = 200 m

Radius of circular track (r) = 200 / 2=100 m

Time taken by the ATHLETE for one round (t) = 40 s

Distance covered by athlete in one round (s) = 2π r

= 2 × ( 22 / 7 ) × 100

Speed of the athlete (v) = Distance / Time

= (2 × 2200) / (7 × 40)

= 4400 / 7 × 40

Therefore, Distance covered in 140 s = Speed (s) × Time(t)

= 4400 / (7 × 40) × (2 × 60 + 20)

= 4400 / (7 × 40) × 140

= 4400 × 140 /7 × 40

= 2200 m

Number of round in 40 s =1 round

Number of round in 140 s =140/40

=3 1/2

Hence, DISPLACEMENT of the athlete with respect to initial POSITION at x= xy

= Diameter of circular track

= 200 m

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