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A body is moving with a uniform speed vin a circular path of radius 7 as shown in figure. Tis period of revolution. The average velocity in section AB isBo27T4T4v2.21 |
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Answer» We know that v=Rω=R(2π/T)=(2πR/T)⟹(R/T)=(v/2π) The average velocity of the PARTICLE for the SEMICIRCULAR path is V av =2R/(T/2)=4R/TSubstituting the value of R/T from PREVIOUS equation, we get V av =4(v/2π)=2v/πHOPE THIS HELPS. |
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