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A body is moving with a uniform speed vin a circular path of radius 7 as shown in figure. Tis period of revolution. The average velocity in section AB isBo27T4T4v2.21​

Answer» <html><body><p>We know that v=Rω=R(2π/T)=(2πR/T)⟹(R/T)=(v/2π) The average velocity of the <a href="https://interviewquestions.tuteehub.com/tag/particle-1147478" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLE">PARTICLE</a> for the <a href="https://interviewquestions.tuteehub.com/tag/semicircular-1200436" style="font-weight:bold;" target="_blank" title="Click to know more about SEMICIRCULAR">SEMICIRCULAR</a> path is V av =2R/(T/2)=4R/TSubstituting the value of R/T from <a href="https://interviewquestions.tuteehub.com/tag/previous-592857" style="font-weight:bold;" target="_blank" title="Click to know more about PREVIOUS">PREVIOUS</a> equation, we get V av =<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>(v/2π)=2v/πHOPE THIS <a href="https://interviewquestions.tuteehub.com/tag/helps-1018140" style="font-weight:bold;" target="_blank" title="Click to know more about HELPS">HELPS</a>.</p></body></html>


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