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A body is projected upwards with a velocity `u`. It passes through a certain point above the ground after `t_(1)`, Find the time after which the body passes through the same point during the journey.A. `((u)/(g)-t_(1)^(2))`B. `2((u)/(g)-t_(1))`C. `3((u^(2))/(g)-t_(1))`D. `3((u^(2))/(g^(2))-t_(1))` |
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Answer» Correct Answer - B Suppose v be the velocity attained by body after time `t_(1)` then `v=u-g t_(1)` …(i) Let the body reach the samepoint at time `t_(2)` now velocity will be downwards with same magnitude v, then `-v=u-g t_(2)` …(ii) `(i)-(iii)implies2v=gU(t_(2)-t_(1))` or `t_(2)-t_(1)=(2v)/(g)=(2)/(g)(u-g t_(1))=2((u)/(g)-t_(1))` |
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