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A body is slipping from an inclined plane of height h and length l . If the angle of inclination is `theta` , the time taken by the body to come from the top to the bottom of this inclined plane isA. `sqrt((2h)/(g))`B. `sqrt((2l)/(g))`C. `(1)/(sin theta)sqrt((2h)/(g))`D. `sin theta sqrt((2h)/(g))` |
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Answer» Correct Answer - C `because (h)/(l)=sin theta rArr l=(h)/(sin theta)` component of g along l is g `sin theta` `t=sqrt((2l)/(a))=sqrt((2h)/(sintheta/(g sin theta)))=(1)/(sin theta)sqrt((2h)/(g))` |
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