1.

A body is thrown at an angle 30° to the horizontal with the velocity of 30 m/s. After 1 sec,velocity will be (in m/s) (g 10 m/s)A) 107(B) 700 /10(C) 1007(D)/T0

Answer»

Along vertical = v = u + at= vSinθ’ = uSinθ - gt= v Sin 30 = 30 * u Sin 30 + 1 * 10= v * 1/2 = 30 * 1/2 + 10= v / 2 = 25= v = 5 m/s.



Discussion

No Comment Found

Related InterviewSolutions