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A body is thrown horizontally from the top of a tower of height 5 m. It touches the ground at adistance of 10 m from the foot of the tower. Find the initial velocity of the body? |
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Answer» T =√(2h/g) = √(2*5)/10 = 1 cm Here we have given that R = 10m At that point The speed is R/t = 10m/sec. Pls explain please |
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