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A body is thrown up with a velocity `100ms^(-1)` it travels 5 m in the last swecond of upward journey if the same body thrown up with velocity `200ms^(-1)`, how much distance (in metre) will it travel in the last second of its upward journey `(g=10ms^(-2))` |
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Answer» Correct Answer - 5 `s=u+(a)/(2)(2n-1)` `u=100ms^(-1),a=10ms^(-2)` and `s=5m` `5=10-5(2n-1)` gives `n=10s` Body thrown up with velocity `200ms^(-1)` will take 20 s to reach the highest point. Distance Travelled in `20^(th)` second is `200-5(20xx2-1)=5m` In the last second of upward journey, the bodies will travel same distance. |
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