1.

A body is thrown up with a velocity `100ms^(-1)` it travels 5 m in the last swecond of upward journey if the same body thrown up with velocity `200ms^(-1)`, how much distance (in metre) will it travel in the last second of its upward journey `(g=10ms^(-2))`

Answer» Correct Answer - 5
`s=u+(a)/(2)(2n-1)`
`u=100ms^(-1),a=10ms^(-2)` and `s=5m`
`5=10-5(2n-1)` gives `n=10s`
Body thrown up with velocity `200ms^(-1)` will take 20 s to reach the highest point. Distance
Travelled in `20^(th)` second is
`200-5(20xx2-1)=5m`
In the last second of upward journey, the bodies will travel same distance.


Discussion

No Comment Found

Related InterviewSolutions