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A body of 2 kg is suspended on a spring balance hung vertically in a lift . If the lift is falling downward under acceleration due to gravity g then what will be the reading of the balance ? If going upward with the same acceleration then ? |
Answer» Reading of the balance = apparent weight ` = m (g-a) = m (g - g ) = zero ` If lift is going upwards with same acc , ` W = m (g - a ) = 2 m g = 4 kg` . |
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