1.

A body of capacitor 6 micro farad is charged to 20V and another body of 4 micro farad is charged to 10V and both are connected with wire the energy lost by the system ispleaase give answer with explanation​

Answer»

Answer:

SOLUTION

Explanation:

Initial ENERGY of body of capacitance 4μF is U

i

=1/2×4×10

−6

×80

2

=0.0128J

Final POTENTIAL on this body after connection is

V=

4+6

4×80+6×30

=50V

so final energy on it,

U

f

=1/2×4×10

−6

×50

2

=0.005J Energy LOST by this body=U

i

−U

f

=7.8mJ


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