1.

A body of mass 0.5 kg travels in straight line with velocity V=ax^(3//2) where a=5m^(-1//2)s^(-1). The work done by the net force durign it's displacement from x=0 to x=2m is

Answer»

15 J
50 J
10 J4%
100 J

Solution :`vecA=(dvecv)/(DT)=2/2a^(2)x^(2),vecF=mvecA`
`W=int_(0)^(2)F ds =50J`


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