A body of mass 0.5 kg is resting on a frictionless surface.When a force of 2000 dyne acts on it for 10 s, then calculate the distance traveled by it in 10 seconds.

A body of mass 0.5 kg is resting on a frictionless surface.When a forc

1.	A body of mass 0.5 kg is resting on a frictionless surface.When a force of 2000 dyne acts on it for 10 s, then calculate the distance traveled by it in 10 seconds.
Answer» <html><body><h3>Required answer :- </h3><p><a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> travelled by the body in 10 seconds is <strong>2</strong><strong> </strong><strong>m</strong><strong> </strong></p><h2><u>EXPLANATION</u><u> </u><u> </u><u>:</u><u>-</u><u> </u></h2><p>As per the given information we have, </p><ul><li><a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of the body is (m) 0.5 kg </li><li>The body is resting of <a href="https://interviewquestions.tuteehub.com/tag/frictionless-1000488" style="font-weight:bold;" target="_blank" title="Click to know more about FRICTIONLESS">FRICTIONLESS</a> surface [u =0] </li><li><a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> acting is 2000 dynes </li><li>Time <a href="https://interviewquestions.tuteehub.com/tag/taken-659096" style="font-weight:bold;" target="_blank" title="Click to know more about TAKEN">TAKEN</a> is 10 s </li></ul><p>We have to find the distance travelled </p><p>From equations of motion, </p><p>We know that , </p><p><img align="absmiddle" alt="\implies \: s = ut + \dfrac{1}{2} at {}^{2}" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%20%5Cimplies%20%5C%3A%20s%20%3D%20ut%20%2B%20%20%5Cdfrac%7B1%7D%7B2%7D%20at%20%7B%7D%5E%7B2%7D%20" title="\implies \: s = ut + \dfrac{1}{2} at {}^{2}"/></p><p>where, </p><ul><li>s = distance covered </li><li>u = initial velocity </li><li>t = time taken </li><li>a = acceleration </li></ul><p>So, we can apply this formula But we don't know the acceleration of the body . So,Lets calculate acceleration of body.</p><p>We know that, </p><p><img align="absmiddle" alt="\implies \: f = ma" class="latex-formula" id="TexFormula2" src="https://tex.z-dn.net/?f=%20%5Cimplies%20%5C%3A%20f%20%3D%20ma" title="\implies \: f = ma"/></p><ul><li>F = force </li><li>m = mass </li><li>a = acceleration </li></ul><p>F = 2000 dynes </p><p>Converting dynes - Newtons</p><p><img align="absmiddle" alt="\implies{F = 2000\times 10^{-5} N }" class="latex-formula" id="TexFormula3" src="https://tex.z-dn.net/?f=%5Cimplies%7BF%20%3D%202000%5Ctimes%2010%5E%7B-5%7D%20N%20%7D" title="\implies{F = 2000\times 10^{-5} N }"/></p><p><img align="absmiddle" alt="\implies{F = 2 \times 10^3× 10^{-5} N}" class="latex-formula" id="TexFormula4" src="https://tex.z-dn.net/?f=%5Cimplies%7BF%20%3D%202%20%5Ctimes%2010%5E3%C3%97%2010%5E%7B-5%7D%20N%7D" title="\implies{F = 2 \times 10^3× 10^{-5} N}"/></p><h3><img align="absmiddle" alt="\implies{F = 2× 10^{-2}N}" class="latex-formula" id="TexFormula5" src="https://tex.z-dn.net/?f=%5Cimplies%7BF%20%3D%202%C3%97%2010%5E%7B-2%7DN%7D" title="\implies{F = 2× 10^{-2}N}"/></h3><h3>F = m × a</h3><p><img align="absmiddle" alt="\implies 2 \times 10 {}^{ - 2} = 0.5 \times a" class="latex-formula" id="TexFormula6" src="https://tex.z-dn.net/?f=%5Cimplies%202%20%5Ctimes%2010%20%7B%7D%5E%7B%20-%202%7D%20%20%3D%200.5%20%5Ctimes%20a" title="\implies 2 \times 10 {}^{ - 2} = 0.5 \times a"/></p><p><img align="absmiddle" alt="\implies \dfrac{2}{100} = \dfrac{5}{10} \times a" class="latex-formula" id="TexFormula7" src="https://tex.z-dn.net/?f=%20%5Cimplies%20%5Cdfrac%7B2%7D%7B100%7D%20%20%3D%20%20%5Cdfrac%7B5%7D%7B10%7D%20%20%5Ctimes%20a" title="\implies \dfrac{2}{100} = \dfrac{5}{10} \times a"/></p><p><img align="absmiddle" alt="\implies \dfrac{2}{10} = 5a" class="latex-formula" id="TexFormula8" src="https://tex.z-dn.net/?f=%20%5Cimplies%20%5Cdfrac%7B2%7D%7B10%7D%20%20%3D%205a" title="\implies \dfrac{2}{10} = 5a"/></p><p><img align="absmiddle" alt="\implies \dfrac{1}{5} = 5a" class="latex-formula" id="TexFormula9" src="https://tex.z-dn.net/?f=%20%5Cimplies%20%5Cdfrac%7B1%7D%7B5%7D%20%20%3D%205a" title="\implies \dfrac{1}{5} = 5a"/></p><p><img align="absmiddle" alt="\implies 25a = 1" class="latex-formula" id="TexFormula10" src="https://tex.z-dn.net/?f=%5Cimplies%2025a%20%3D%201" title="\implies 25a = 1"/></p><p><img align="absmiddle" alt="\implies a = \dfrac{1}{25} \: m/s {}^{2}" class="latex-formula" id="TexFormula11" src="https://tex.z-dn.net/?f=%5Cimplies%20a%20%3D%20%20%5Cdfrac%7B1%7D%7B25%7D%20%20%5C%3A%20m%2Fs%20%7B%7D%5E%7B2%7D%20" title="\implies a = \dfrac{1}{25} \: m/s {}^{2}"/></p><p>Substituting these values in formula </p><p><img align="absmiddle" alt="\implies \: s = ut + \dfrac{1}{2} at {}^{2}" class="latex-formula" id="TexFormula12" src="https://tex.z-dn.net/?f=%20%5Cimplies%20%5C%3A%20s%20%3D%20ut%20%2B%20%20%5Cdfrac%7B1%7D%7B2%7D%20at%20%7B%7D%5E%7B2%7D%20" title="\implies \: s = ut + \dfrac{1}{2} at {}^{2}"/></p><p><img align="absmiddle" alt="\implies \: s = 0(10) + \dfrac{1}{2} \times \dfrac{1}{25} \times (10) {}^{2}" class="latex-formula" id="TexFormula13" src="https://tex.z-dn.net/?f=%20%5Cimplies%20%5C%3A%20s%20%3D%200%2810%29%20%2B%20%20%5Cdfrac%7B1%7D%7B2%7D%20%20%5Ctimes%20%20%5Cdfrac%7B1%7D%7B25%7D%20%20%5Ctimes%20%2810%29%20%7B%7D%5E%7B2%7D%20" title="\implies \: s = 0(10) + \dfrac{1}{2} \times \dfrac{1}{25} \times (10) {}^{2}"/></p><p><img align="absmiddle" alt="\implies \: s = \dfrac{1}{50} \times 100" class="latex-formula" id="TexFormula14" src="https://tex.z-dn.net/?f=%20%5Cimplies%20%5C%3A%20s%20%3D%20%20%5Cdfrac%7B1%7D%7B50%7D%20%20%5Ctimes%20100" title="\implies \: s = \dfrac{1}{50} \times 100"/></p><p><img align="absmiddle" alt="\implies \: s = 2m" class="latex-formula" id="TexFormula15" src="https://tex.z-dn.net/?f=%20%5Cimplies%20%5C%3A%20s%20%3D%20%202m" title="\implies \: s = 2m"/></p><p>So, distance travelled in 10 seconds by the body is 2m</p></body></html>

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A body of mass 0.5 kg is resting on a frictionless surface.When a force of 2000 dyne acts on it for 10 s, then calculate the distance traveled by it in 10 seconds.

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