1.

a body of mass 1.5 kg is thrown vertically upwards with an initial velocity of 15m/s. what will be th3e potential energy at the end of 2sec. (g=10m/s)

Answer»

The height to which the BODY REACHES after 2 seconds
S = ut + 1/2a t^2
= 15*2 - (1/2 * 10 * 4)
= 30 - 20
= 10 m
Potential energy gained by body = mgh = 1.5 * 10 * 10 = 150 J



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